Valuation, depreciation and the rate base

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Monograph

Identifikator:: 174667931X

URN:: urn:nbn:de:zbw-retromon-119897

Document type:: Monograph

Author:: Grunsky, Carl Ewald http://d-nb.info/gnd/10180959X

Title:: Valuation, depreciation and the rate base

Edition:: 2. ed., revised and extended

Place of publication:: New York

Publisher:: Wiley

Year of publication:: 1927

Scope:: X, 500 Seiten

Digitisation:: 2021

Collection:: Economics Books

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Document type:: Monograph

Structure type:: Chapter

Title:: Chapter XVII. Supplement to valuation, depreciation and the rate-base

Collection:: Economics Books

434 VALUATION, DEPRECIATION AND THE RATE-BASE Then the expectancy to be determined will be found from ne’ £i= (32) Example. — What is the expectancy of an article 8 years old, in fair condition, whose probable life new was 12 years? Here n = 12 and m = 8. 8 m = el 6.67. 12 For the age 6.67 years in the ten-year subdivision of Table 31 (this being in the seventh year) the expectancy 5.17 years is found by interpolation. The required expectancy is, therefore, — 517 X= =6 e = 5.17 X — = 06.2 years, which would be found in a twelve-year probable life table for the end of the eighth year or for the beginning of the ninth year. For general use the following formula are recommended which will be found to agree fairly well with the results presented in Table 31. They are applicable to any probable life term and any age to the limit beyond which the assumption is justified that no article will continue in service. When the age of an article is less than its probable life term new, that is, when m < n m2 ¢ =~ 003m + o30-". (33) When the age of an article is greater than its probable life term new, that is, when m > #» e =0.72% — 0.35 M. (34) Example. — What is the expectancy of an article whose probable term of usefulness when new was 12 years, which is 8 years old and apparently in good condition? Here n = 12 and m = 8.

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